15188198
15188198 15188198
  • 14-12-2022
  • Mathematics
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An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the object's height s at time t seconds after launch is s(t)= -4.9t^2 + 19.6t + 58.8, where s is in meters. How high will the object be after 3 seconds
73.5 ft
98.49 ft
161.7 ft
333.69 ft

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