penguinsydney4164 penguinsydney4164 15-02-2024 Mathematics contestada What is the solution to the equation 2cos(2x)cos(x)-2sin(2x)sin(x)=-√2?A) 2cos(2x)cos(x)-2sin(2x)sin(x)=-√2B) cos(2x)cos(x)-sin(2x)sin(x)=-√2C) cos(2x)cos(x)-sin(2x)sin(x)=√2D) cos(2x)cos(x)-sin(2x)sin(x)=√2
