maddycat8657 maddycat8657

12-05-2018
Chemistry

contestada

The ionization constant for water (kw) is 9.614*10-14 at 60°c. calculate [h3o+], [oh−], ph, and poh for pure water at 60°c.

Respuesta :

Dejanras Dejanras

24-05-2018

The Kw (the ionic product for water) at 60°C is 9.614·10⁻¹⁴ mol²/dm⁶.
Kw = [H₃O⁺] · [OH⁻].
[H₃O⁺] = [OH⁻] = √9.614·10⁻¹⁴ mol²/dm⁶.
[H⁺] = [OH⁻] = 3.1·10⁻⁷ mol/L.
pH = -log[H₃O⁺].
pH = -log(3.1·10⁻⁷ mol/L).
pH = 6.5; potential of hydrogen of neutral solution at 60°C.
pOH = -log[OH⁻].
pOH = 6.5.

Answer Link

Otras preguntas

Let a=(?2,1,2, b=(?1,2,4, and p=(k,k,k. the vector from a to b is perpendicular to the vector from a to p when k =

HELP PICTURE IS INCLUDEX

Warm-Up Topic: Can an 18 year old kid carry a handgun while in foster care? The second amendment states we have the right to "bare arms". And in PA you can Car

why was the battle of san jacinto important?

Because of possible exposure to the parasite toxoplasma gondii, some studies suggest that people who own a ____ are more likely to have children who become schi

What is an antonym for telltale

The first organism in a food chain muust always be what type e of organism

inference are logical explanations of observation combined with the scientists what

Yucca moths lay eggs in yucca flowers. When the eggs hatch, the larvae eat yucca seeds. The moths help pollinate the flowers. What type of symbiosis is this?

5/3+5/3+5/3 = how to solve