Respuesta :

sqdancefan
Your supposition requires that

[tex]3\leq \dfrac{f(5)-f(1)}{5-1} \leq 4\\\\12 \leq (f(5)-f(1)) \leq 16[/tex]

The minimum possible value of f(5)-f(1) is 12.
The maximum possible value of f(5)-f(1) is 16.

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