Respuesta :

calculista
we have that
f(x) = x² + 3x + 6
and
g(x) = (x - 3)/2

step 1
solve for f(g(x)) when x = 1.

We want to evaluate f(g(1))

So g(x) = (x - 3)/2   

when x =1

g(1) = (1 - 3) /2 = -2/2 = -1

So

f(g(1)) = f(-1) = (-1)² + 3(-1) + 6 =  1 - 3 + 6 = 4

the answer is

4

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