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Rationalize the denominator of square root of negative 9 over open parentheses 4 minus 7 i close parentheses minus open parentheses 6 minus 6 i close parenthe . (6 points)
1. quantity of negative 3 minus 6 i over 5
2. quantity of 39 minus 6 i over negative 9
3. quantity of negative 39 minus 6 i over 17
4. quantity of 3 minus 6 i over 3

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sqdancefan
A calculator shows
[tex]\dfrac{\sqrt{-9}}{(4-7i)-(6-6i)}=\dfrac{3i}{-2-i}=-3\cdot\dfrac{i(2-i)}{2^2+1^2}\\\\=\dfrac{-3-6i}{5}[/tex]

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