[tex]8x^2=6+22x\ \ \ \ |-22x-6\\\\8x^2-22x-6=0\ \ \ |:2\\\\4x^2-11x-3=0\\\\4x^2-12x+x-3=0\\\\4x(x-3)+1(x-3)=0\\\\(x-3)(4x+1)=0\iff x-3=0\ \vee\ 4x+1=0\\\\x-3=0\ \ \ |+3\\x=3\\\\4x+1=0\ \ \ |-1\\4x=-1\ \ \ |:4\\x=-0.25[/tex]
Answer: x = 3 or x = -0.25
