[tex]8x^2-18x=0\\\\2x\cdot4x-2x\cdot9=0\\\\2x(4x-9)=0[/tex]
Solution:
[tex]2x(4x-9)=0\iff2x=0\ \vee\ 4x-9=0\\\\2x=0\ \ \ |:2\\\\x=0\\\\4x-9=0\ \ \ |+9\\\\4x=9\ \ \ \ |:4\\\\x=2.25[/tex]
Answer:
[tex]\boxed{x=0\ \text{or}\ x=2.25}[/tex]
