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12-08-2018
Chemistry

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How many moles of HCl are present in 4.7 L of a 4.23 M HCl solution?

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Willchemistry Willchemistry

12-08-2018

Hey There!

Volume = 4.7 L

Molarity = 4.23 M

Therefore:

n = M *V

n = 4.23 * 4.7

n = 19.881 moles of HCl

hope this helps!

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