[tex] (g\circ f)(x)=\dfrac{6}{\dfrac{2}{x-3}}=6\cdot\dfrac{x-3}{2}=3x-9\\\\\\(g\cdot f)(x)=\dfrac{6}{x}\cdot \dfrac{2}{x-3}=\dfrac{12}{x^2-3x} [/tex]
