kayden413
kayden413 kayden413
  • 11-09-2018
  • Mathematics
contestada

Solve for n.

2n-3/5 = 5.

Solve for n 2n35 5 class=

Respuesta :

konrad509
konrad509 konrad509
  • 11-09-2018

[tex]\dfrac{2n-3}{5}=5\\\\ 2n-3=25\\\\ 2n=28\\\\ n=14[/tex]

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