[tex]\dfrac{4x-8}{-3x}\cdot\dfrac{12}{12-6x}=\dfrac{4(x-2)}{-x}\cdot\dfrac{4}{-6(x-2)}=\dfrac{4}{-x}\cdot\dfrac{4}{-6}\\\\=\dfrac{2}{-x}\cdot\dfrac{4}{-3}=\dfrac{(2)(4)}{(-x)(-3)}=\dfrac{8}{3x}[/tex]
