mariajobrianna mariajobrianna
  • 16-10-2018
  • Mathematics
contestada

find the cube root of 1/27

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jdoe0001 jdoe0001
  • 16-10-2018

[tex]\bf \sqrt[3]{\cfrac{1}{27}}~~\begin{cases}1^3=1\\27=3^3\end{cases}\implies \sqrt[3]{\cfrac{1^3}{3^3}}\implies \cfrac{\sqrt[3]{1^3}}{\sqrt[3]{3^3}}\implies \cfrac{1}{3}[/tex]

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bernjungkind
bernjungkind bernjungkind
  • 16-10-2018

1/3is the answer to this

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