there are no signs between the x and y and constant
it could be
2x+5y=15
2x+5y=-15
-2x+5y=15
2x-5y=15
for ax+by=c, the equation of a line paralell to that is
ax+by=d where a=a, b=b, and c and d are constants
(for this answer, I'm going to use 2x+5y=15)
given 2x+5y=15, the equation of a line paralell to that is 2x+5y=d
to find d, subsitute the point (4,-2), basically put 4 in for x and -2 for y to get the constant
2x+5y=d
2(4)+5(-2)=d
8-10=d
-2=d
the eqaution is 2x+5y=-2 (Only if the original equation is 2x+5y=-15
The southbound track and the northbound track are illustrations of linear functions, where the equation of the northbound track is [tex]2x + 5y = -2[/tex]
The equation of the southbound track is given as:
[tex]2x + 5y = 15[/tex]
A linear equation is of the form
[tex]Ax + By =C[/tex]
From the question, we understand that the northbound track is parallel to [tex]2x + 5y = 15[/tex]
This means that:
[tex]A = 2[/tex]
[tex]B = 5[/tex]
So, we have:
[tex]2x + 5y = C[/tex]
The track also runs through (4,-2).
This means that: [tex](x,y) = (4,-2)[/tex]
So, we have:
[tex]2x + 5y = C[/tex]
[tex]2 \times 4 + 5 \times -2 = C[/tex]
[tex]8- 10 = C[/tex]
[tex]-2 = C[/tex]
[tex]C =-2[/tex]
Substitute [tex]C =-2[/tex] in [tex]2x + 5y = C[/tex]
[tex]2x + 5y = -2[/tex]
Hence, the equation of the parallel northbound is [tex]2x + 5y = -2[/tex]
Read more about linear functions at:
https://brainly.com/question/20286983
