alexandriajo
alexandriajo alexandriajo
  • 11-12-2018
  • Physics
contestada

A lightbulb has a resistance of 195 ohms and carries a current of 0.62 A. The power rating of the lightbulb, to the nearest whole number is blank W.

Respuesta :

jcherry99
jcherry99 jcherry99
  • 16-12-2018

Wattage = I^2 * R

R = 195 ohms

I = 0.62 A

Wattage = 0.62^2 * 195

Wattage = 74.958

Wattage = 75 watts to the nearest whole watt.

Answer Link
anp05 anp05
  • 19-04-2022

Answer:

75 w

Explanation:

Answer Link

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