Let [tex]x[/tex] by the smallest of the 6 integers. Then
[tex]x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=204[/tex]
[tex]\implies6x+15=204[/tex]
[tex]\implies6x=189[/tex]
But 189 is odd, so it cannot be divisible by 6, which means [tex]x[/tex] is not an integer...
