Answer: [tex]f(x) = (2x+1)(2x+3)[/tex]
Step-by-step explanation:
Since, the given function,
[tex]f(x)=2(2x^2+4x)+3[/tex]
⇒ [tex]f(x)=4x^2+8x+3[/tex]
⇒ [tex]f(x)=4x^2+6x+2x+3[/tex]
⇒ [tex]f(x)=2x(2x+3)+1(2x+3)[/tex]
⇒ [tex]f(x)=(2x+1)(2x+3)[/tex]
Since, this form of f(x) reveals the zeros of f(x).
Therefore, this is the required form.
