Respuesta :

5naka

by pythagorean formula, the last side is √(61)

by cos rule

cos A

[tex] = \frac{ {6}^{2} + 61 - {5}^{2} }{2 \times 6 \times \sqrt{61} } \\ = \frac{72}{12 \sqrt{61} } \\ = \frac{6}{ \sqrt{61} } [/tex]

A = 39.81

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