Answer:
[tex](\frac{1}{3}x + 1)(x - 2)[/tex]
x = -3 or 2
Step-by-step explanation:
Given the following polynomial:
[tex]\frac{1}{3}x^{2}+\frac{1}{3}x-2[/tex]
we can factor into two binomials:
[tex](\frac{1}{3}x+1)(x-2)[/tex]
set the two binomials equal to '0' and solve for 'x':
[tex]\frac{1}{3}[/tex]x + 1= 0 x - 2 = 0
x = -3 x = 2
