Respuesta :

5naka

by pythagorean

AC² = AB² + BC²

AC² = 6² + 8² = 100

AC = 10

m<B = m<D and m<E = m<C,

by AA ∆ABC ~ ∆CDE

CE/AC = CD/AB

CE = AC•CD/AB

CE = 10•4/6 = 20/3

hence

AE = AC + CE

= 10 + 20/3

= 50/3

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