the force is given by the equation
q*v*B sin@
thus it will be
(1.6*10^-19)*(7.8*10^4)*(3)*1/√2 which gives 2.6*10^-14 N
Formula
F = q*v*B Sin (theta)
Givens
q = 1.6*10^-19 coulombs
v = 7.8*10^4 m/s
B = 3 Tesla
phi = 45 degrees.
Solution
F = q*v*B * sin(45)
F = 1.6*10^-19 * 7.8*10^4 * 3 * Sin(45)
F = 2.6 * 10 ^-14
D
