Answer:
[tex]\large\boxed{y-1=-\dfrac{1}{5}(x-2)}[/tex]
Step-by-step explanation:
The point-slope form of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
(x₁, y₁) - point
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (-3, 2) and (2, 1). Substitute:
[tex]m=\dfrac{1-2}{2-(-3)}=\dfrac{-1}{5}=-\dfrac{1}{5}[/tex]
[tex]y-1=-\dfrac{1}{5}(x-2)[/tex]
