Answer:
[tex]\large\boxed{(n-8)(n+2)=n^2-6n-16}[/tex]
Step-by-step explanation:
Use FOIL:
(a + b)(c + d) = ac + ad + bc + bd
We have:
[tex](n-8)(n+2)=(n)(n)+(n)(2)+(-8)(n)+(-8)(2)=n^2+2n-8n-16[/tex]
combine like terms
[tex]=n^2+(2n-8n)-16=n^2-6n-16[/tex]
