Answer:
[tex]\large\boxed{(g\circ f)(1)=16}[/tex]
Step-by-step explanation:
[tex]f(x)=7x-3\\\\g(x)=x^2\\\\(g\circ f)(x)\to\text{substitute (7x - 3) to the function}\ g(x):\\\\(g\circ f)(x)=(7x-3)^2\\\\(g\circ f)(1)\to\text{put x = 1:}\\\\(g\circ f)(1)=(7\cdot1-3)^2=(7-3)^2=(4)^2=16[/tex]
