sareena880 sareena880

14-05-2019
Mathematics

contestada

[tex] 2 {r}^{2} - 4r - 16[/tex]

Respuesta :

jcherry99 jcherry99

14-05-2019

Answer:

Step-by-step explanation:

Take out a common factor of 2

2(r^2 - 2r - 8) Now factor.

2(r - 4)(r + 2)

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prosborough198p2ub41 prosborough198p2ub41

14-05-2019

Answer: r=4,-2

2r^2-4r-16=0

2(r^2-2r-8)=0

2(r-4)(r+2)=0

r=4,-2

Answer Link

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