Answer:
[tex]\large\boxed{\dfrac{1}{45}}[/tex]
Step-by-step explanation:
1.
2 yellow marables of 10 all marables
[tex]P(A_1)=\dfrac{2}{10}=\dfrac{1}{5}[/tex]
2.
1 yellow marable of 9 all marables
[tex]P(A_2)=\dfrac{1}{9}[/tex]
[tex]P(A)=P(A_1)\cdot P(A_2)\\\\P(A)=\dfrac{1}{5}\cdot\dfrac{1}{9}=\dfrac{1}{45}[/tex]
