Answer:
Option C is correct
Step-by-step explanation:
We need to simplify the radical
[tex]\sqrt{\frac{20x^{13}y^5}{5xy^7}}[/tex]
We know that a^m/a^n = a^m-n and 20/5 = 4
Solving
[tex]\sqrt{4x^{13-1}y^{5-7}}\\\sqrt{4x^{12}y^{-2}}\\[/tex]
Now, √4 = 2 and a^-m = 1/a^m
Applying,
[tex]2\sqrt{\frac{x^{12}}{y^2}}\\[/tex]
So, Option C [tex]2\sqrt{\frac{x^{12}}{y^2}}\\[/tex] is correct.
