Answer:
[tex]\large\boxed{(3-2i)(3+2i)=13}[/tex]
Step-by-step explanation:
[tex](3-2i)(3+2i)\qquad\text{use}\ (a-b)(a+b)=a^2-b^2\\\\=3^2-(2i)^2=9-4i^2\qquad i=\sqrt{-1}\to i^2=-1\\\\=9-4(-1)=9+4=13[/tex]
