Answer:
[tex]5b\left(b+1\right)\left(b+12\right)[/tex]
Step-by-step explanation:
[tex]5b^3+65b^2+60b\\\mathrm{Factor\:out\:common\:term\:}5b:\quad 5b\left(b^2+13b+12\right)\\=5b\left(b^2+13b+12\right)\\\mathrm{Factor}\:b^2+13b+12:\quad \left(b+1\right)\left(b+12\right)\\=5b\left(b+1\right)\left(b+12\right)[/tex]
