Answer:
[tex]\dfrac{2x}{3a^2}[/tex]
Step-by-step explanation:
[tex]\dfrac{3a^4b}{2x}\cdot\dfrac{4x^2}{9a^6b}=\dfrac{3\cdot 4}{2\cdot 9}a^{4-6}b^{1-1}x^{2-1}=\dfrac{2x}{3a^2}[/tex]
The applicable rules of exponents are ...
- (a^b)(a^c) = a^(b+c)
- a^-b = 1/a^b
