Respuesta :

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Evaluate int[sin^3(θ)cos(θ)dθ] with u = sin(θ)
du/dθ = cos(θ), dθ = du/cos(θ)

The integral becomes:
int[u^3•cos(θ)du/cos(θ)]
= int[u^3•du]
= u^4/4 + C

Substitute u = sin(θ) to get back a function of θ:
sin^4(θ)/4 + C

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