Answer:
option D
Step-by-step explanation:
[tex]x^{2} + y^{2} = 16\\\\x^{2} = 16- y^{2}[/tex]
equation 2:
[tex]\frac{x^{2}}{4} - \frac{y^{2}}{25} = 1[/tex]
so we have:
[tex]\frac{16- y^{2} }{4}-\frac{y^{2}}{25}= 1[/tex]
