Answer:
The value of h must be greater than or equal to 8 inches
The minimum value of h is 8 inches
Step-by-step explanation:
Let
h ----> the possible heights (in inches) of the triangle
we know that
The area of triangle is equal to
[tex]A=\frac{1}{2}bh[/tex]
where
b is the base length
h is the height
In this problem we have
[tex]b=4\ in[/tex]
Remember that the word "at least" means "greater than or equal to"
so
[tex]A\geq 16\ in^2[/tex]
The inequality that represent this problem is
[tex]\frac{1}{2}bh\geq 16[/tex]
substitute the value of b
[tex]\frac{1}{2}(4)h\geq 16[/tex]
[tex]2h\geq 16[/tex]
[tex]h\geq 8\ in[/tex]
The value of h must be greater than or equal to 8 inches
The minimum value of h is 8 inches
