Answer:
Step-by-step explanation:
2x-3y=6
-3y = -2x + 6
y = -2x/-3 + 6/ -3
y = 2x/3 - 2 {y =mx + c}
slope = 2/3
The required line's slope is also 2/3 as it is parallel to this line
Point(9, -3)
y -y1 = m(x-x1)
y - (-3) = 2/3 (x - 9)
y + 3 = 2x/3 - 2*9/3
y + 3 =2x/3 - 2*3
y + 3 = 2x/3 -6
y = 2x/3 - 6 - 3
y = 2x/3 - 9
