Answer:
x^2 +3x +9
Step-by-step explanation:
The factoring of the difference of cubes is a standard form you should keep handy:
a³ -b³ = (a -b)(a² +ab +b²)
Here, you have a=x, b=3, so the division is ...
[tex]\dfrac{x^3-27}{x-3}=\dfrac{(x-3)(x^2+3x+9)}{x-3}=x^2+3x+9[/tex]
There is no remainder.
