Answer:
The answer to your question is: [tex]2\sqrt{6} b + 2\sqrt{15} c[/tex]
Step-by-step explanation:
10[tex]\sqrt{6} b[/tex] + 5 [tex]\sqrt{15} c - 8\sqrt{6} b - 3\sqrt{15} c[/tex]
Simplify like terms
[tex](10\sqrt{6} b - 8\sqrt{6} b) + (5\sqrt{15} c - 3\sqrt{15} c )[/tex]
[tex]2\sqrt{6} b + 2\sqrt{15} c[/tex]
