Answer:
[tex]\ln (3x^{6}) = 16[/tex]
Step-by-step explanation:
Here's one way to do it.
[tex]\begin{array}{rcl}\ln (3x^{3}) + 3 \ln x & = & 16\\\ln (3x^{3}) + \ln(x^{3}) & = & 16\\\ln (3x^{3}\cdot x^{3})& = & 16\\\ln (3x^{6})& = & 16\\\end{array}[/tex]
