lawrenceflorez lawrenceflorez

14-11-2019
Mathematics

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Please HElp!! What is the equation of a circle with its center at (−6,−3) and a radius of 12? `
(x+6)2+(y+3)2=144
(x−6)2+(y−3)2=12
(x−6)2+(y−3)2=144
(x+6)2+(y+3)2=12
(x+6)2+(y+3)2=24

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Аноним Аноним

14-11-2019

Given the center (a,b) and the radius r, the equation of the circle is

[tex](x-a)^2+(y-b)^2=r^2[/tex]

Plug your values a = -6, b = -3, r = 12

[tex](x+6)^2+(y+3)^2=144[/tex]

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