Answer:
R = 125Ω
Explanation:
Use the equation for voltage:
V = IR
V is voltage, in volts V
I is current, in amperes A
R is resistance, in ohms Ω
Substitute V for 25V and I for 0.2A
V = IR
(25V) = (0.2A)R Isolate R for resistance. Divide both sides by 0.2
R = 125Ω
The resistance for the lightbulb is 125 Ω.
