olvera2516 olvera2516

15-12-2019
Chemistry

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A gas is 90.82L at 29.8 atm and 99.9°C. What volume would the gas be at standard temperature and pressure.

Respuesta :

shakha2017 shakha2017

15-12-2019

Answer:

1981.38L

Explanation:

P=29.8atm;

T=273+99.9=372.9⁰K

V=90.82L

P₀=1atm

T₀=273⁰K

V₀-?

PV/T=P₀V₀/T₀

V₀=PVT₀/P₀T=

[tex] = \frac{29.8 \times 90.82 \times 273}{1 \times 372.9} = 1981.38l[/tex]

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