Respuesta :

caylus
Hello,

Answer 2

=ln(6)*ln(6)/(ln(2)*ln(3))-ln(3)/ln(2)-ln(2)/ln(3)
=((ln(6))²-(ln(3))²-(ln(2))²)/(ln(2)*ln(3))
=2

Let's assume
a=ln (6)
b=ln(3)
c=ln(2)
6=2*3 ==>a=b+c
a²=(b+c)²=b²+c²+2bc ==> a²-b²-c²=2bc

2bc/bc=2



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