Answer:
3.4321229*10^23 molecules.
Explanation:
1 mole of CBr4 contains 6.0221409*10^23 molecules (Avogadro's Number).
The molar mass of this compound is 12.011 + 4(79.904)
= 331.627 g.
So the answer is (189/ 331.627) * 6.0221409*10^23
= 3.4321229*10^23 molecules.
