Answer:
Dissolve 190 grams of silver nitrate in 250 mL of water.
Step-by-step explanation:
First, find the moles of AgNO₃ from the volume and concentration.
0.250 L × 4.5 mol/L = 1.125 mol
Next, find the mass of AgNO₃ using the molar mass.
1.125 mol × 170 g/mol = 191.25 g
Rounded to two significant figures, dissolve 190 grams of silver nitrate in 250 mL of water.
