Respuesta :

LammettHash

The average value of [tex]f(x)[/tex] over [0, 8] is

[tex]\displaystyle\frac1{8-0}\int_0^8\sqrt{x+1}\,\mathrm dx=\frac1{12}(x+1)^{3/2}\bigg|_0^8=\frac{13}6[/tex]