Answer:
[tex]\frac{1}{1+e^x}[/tex]
Step-by-step explanation:
We are given: [tex]y = \ln( \frac{e^x}{1+e^x} )[/tex]
The Division and Logarithm properties of the Derivative will be used.
[tex]y' =\frac{\frac{e^x(1+e^x)-e^xe^x}{(1+e^x)^2}}{\frac {e^x}{1+e^x}} =\frac{1}{1+e^x}[/tex]
