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15-01-2020
Chemistry

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How is C10 H16 + 8 Cl2+ 10C + 16 HCL written

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15-01-2020

Answer:

10 C-8/5 - 16 e- → 10 C0 (oxidation)

16 Cl0 + 16 e- → 16 Cl-I (reduction)

Explanation:

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