Answer:
0.054 M
Explanation:
A high blood alcohol concentration is considered to be 0.25 g/dL. We will express it in g/L, considering that 1 L = 10 dL.
0.25 g/dL × (10 dL/1 L) = 2.5 g/L
The molar mass of this blood alcohol (ethanol) is 46.07 g/mol. The molarity of this alcohol (moles of solute per liter of solution) is:
2.5 g/L × (1 mol/46.07 g) = 0.054 mol/L = 0.054 M
