Answer:
The diameter would be 6.
Step-by-step explanation:
Hello!
We use the formulas:
[tex]\boxed{A= \pi r^2}[/tex]
[tex]\boxed{d=2r}[/tex]
Solving for d:
[tex]d=2\sqrt{\frac{A}\pi r} } =2 \times\sqrt{\frac{28.3}{\pi} } =6[/tex]
Hope this helps!
Hugs and wishes,
Josh
