Answer:
x = 2/3
Step-by-step explanation:
[tex]\dfrac{x-4}{x+1}-\dfrac{x}{x-1}=0\\\\\dfrac{(x-4)(x-1)-x(x+1)}{(x+1)(x-1)}=0\\\\\dfrac{-6x+4}{x^2-1}=0 \quad\text{0 when the numerator is zero}\\\\x-\dfrac{2}{3}=0 \quad\text{divide by $-6$}\\\\x=\dfrac{2}{3}[/tex]
