Answer:
3.5 and 5
Step-by-step explanation:
Given
f(x) = [tex]\frac{x+5}{x}[/tex]
To evaluate f(2) substitute x = 2 into f(x)
f(2) = [tex]\frac{2+5}{2}[/tex] = [tex]\frac{7}{2}[/tex] = 3.5
Similarly for [tex]f^{-1}[/tex](x)
[tex]f^{-1}[/tex] (2 ) = [tex]\frac{5}{2-1}[/tex] = 5
